In a mixture, milk and water are in ratio of 2: 3. Some milk is added to the mixture because of which ratio of milk and water becomes 10: 3. How much milk was added as a percentage of initial mixture?

Correct option is C

Given:

In a mixture, milk and water are in the ratio of 2:3. After adding some milk, the ratio becomes 10:3.
Formula Used:
Initial milk = 2 parts Initial water = 3 parts New milk = Initial milk + Added milk Ratio = New milk / Water
Solution:
Let the initial quantity of milk be 2x and water be 3x. After adding milk, let the new quantity of milk be 10y and water be 3y. Given that the amount of water remains unchanged, 3x = 3y, thus x = y. The amount of milk added = 10y - 2x = 8y. Percentage of milk added = (8y / (2x + 3x)) × 100 = 160%.
Alternate Method:

Required result = 24/15× 100 = 160% 

Alternative Method: 

Milk and water are in the ratio of 2:3 

After adding some milk, the ratio becomes 10:3

There is no change in the quantity of water ( 3 unit)  because only milk is added  

Added  milk = ( 10 - 2) unit = 8 unit 

Initial quantity of mixture = 2 + 3 = 5 unit 

Percentage of milk added= $$\frac{8}{5} \times 100 \%$$  = 160% 

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