In a joint family, there are father, mother, 3 married sons and one unmarried daughter. Of the sons, two have 2 daughters each and one has a son. Find the ratio of the total number of female members to the total number of male members in the family:

Correct option is B

Given:

In a joint family, there are father, mother, 3 married sons and one unmarried daughter. Of the sons, two have 2 daughters each and one has a son. Find the ratio of the total number of female members to the total number of male members in the family.

- Family Members:

- Father and Mother: 1 male, 1 female.

- Sons: 3 males and their wives: 3 females.

- One unmarried daughter: 1 female.

- Children of sons:

- Two sons have 2 daughters each: 2 × 2 = 4 females.

- One son has 1 son: 1 male.

Solution:

Total Male Members:

The total number of males is calculated as:

Total males = Father + Sons + Son's son

Total males = 1 + 3 + 1 = 5

Total Female Members:

The total number of females is calculated as:

Total females = Mother + Wives of sons + Unmarried daughter + Daughters of sons

Total females = 1 + 3 + 1 + 4 = 9

Ratio of Female Members to Male Members:

The ratio is given by:

Ratio = $$\frac{Total females}{Total males}$$​

Ratio = $$\frac{9}{5}$$​

Final Answer:

The ratio of female members to male members is: $$\boxed{9:5}$$​