​In a box containing one rupee, 50 paise and 25 paise coins in the ratio 1 : 2 : 3, the number of 50 paise coins was eighty. How much money was there in the box? ​

Correct option is D

Given:

The ratio of one rupee coins, 50 paise coins, and 25 paise coins is 1 : 2 : 3.

The number of 50 paise coins is eighty.

Solution:

Let the number of one rupee coins be x, 50 paise coins is 2x , 25 paise coins is 3x 

The number of 50 paise coins is 80:

2x = 80 

x = $$\frac{80}{2}$$ = 40

​Now, 

One rupee coins: x = 40

50 paise coins: 2x = 80

25 paise coins: 3x=120 

The total amount of money:

One rupee coins (40 coins): 40×1 rupee = 40 rupees

50 paise coins (80 coins): 80×0.50 rupees = 40 rupees

25 paise coins (120 coins): 120×0.25 rupees = 30 rupees

40 rupees + 40 rupees + 30 rupees = 110 rupees

So, the total money in the box is 110 rupees.

Thus, correct answer is (d) 110 rupees