In a batch of 13 students 4 have failed. The marks of the successful candidates were 41,57,38,61,36,35,71,50 and 40 . Find the median marks:

Total students: 13

Students who failed: 4

Marks of successful candidates:

41, 57, 38, 61, 36, 35, 71, 50, 40

Sort the marks of successful candidates in ascending order:

35, 36, 38, 40, 41, 50, 57, 61, 71

Ascending order will be _, _, _, _, 35, 36, 38, 40, 41, 50, 57, 61, 71

Total no of student = 13

Determine the position of the median:

For n = 13 (odd), the median is the $$\left( \frac{n+1}{2} \right)^{\text{th}}$$​ value:
​$$\text{Median position} = \frac{13+1}{2} = 7^{th}$$​

The 7th value in the sorted list:_, _, _, _, 35, 36, 38, 40, 41, 50, 57, 61, 71

The median marks are 38.

Correct answer is (d) 38.