arrow
arrow
arrow
If y=log√e(sinx)y = log_{√e}(sin x)y=log√e​(sinx) then dydx\frac{dy}{dx}dxdy​ is :​
Question

If y=loge(sinx)y = log_{√e}(sin x) then dydx\frac{dy}{dx} is :​

A.

ecotx\sqrt e \cot x \\​​

B.

1ecotx\frac{1}{\sqrt e} \cot x \\​​

C.

2cotx2 \cot x \\​​

D.

12cotx\frac{1}{2} \cot x​​

Correct option is C

Given:
y=loge(sinx)y = \log_{\sqrt{e}}(\sin x)​​
Concept used:
logab=lnblna,andddx(ln(sinx))=cotx\log_a b = \frac{\ln b}{\ln a}, and \frac{d}{dx}(\ln(\sin x)) = \cot x​​
Solution:
y=ln(sinx)ln(e) ln(e)=ln(e1/2)=12y = \frac{\ln(\sin x)}{\ln(\sqrt{e})} \\ \ \\\ln(\sqrt{e}) = \ln(e^{1/2}) = \frac{1}{2}​​
So,
y=ln(sinx)1/2=2ln(sinx)y = \frac{\ln(\sin x)}{1/2} = 2\ln(\sin x)​​
Differentiate:
dydx=2×cosxsinx=2cotx\frac{dy}{dx} = 2 \times \frac{\cos x}{\sin x} = 2\cot x​​
Correct answer is (c) 2cotx2 \cot x \\​​

Free Tests

Free
Must Attempt

UPTET Paper 1: PYP Held on 23rd Jan 2022 (Shift 1)

languageIcon English
  • pdpQsnIcon150 Questions
  • pdpsheetsIcon150 Marks
  • timerIcon150 Mins
languageIcon English
Free
Must Attempt

UPTET Paper 2 Social Science : PYP Held on 23rd Jan 2022 (Shift 2)

languageIcon English
  • pdpQsnIcon150 Questions
  • pdpsheetsIcon150 Marks
  • timerIcon150 Mins
languageIcon English
Free
Must Attempt

UPTET Paper 2 Maths & Science : PYP Held on 23rd Jan 2022 (Shift 2)

languageIcon English
  • pdpQsnIcon150 Questions
  • pdpsheetsIcon150 Marks
  • timerIcon150 Mins
languageIcon English

Similar Questions

test-prime-package

Access ‘EMRS TGT’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
347k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow