Find $$\frac{dy}{dx}$$​ given the following implicit equation: $$x^2+y^2=a^2$$

Correct option is B

​$$\text{Differentiating implicitly:} \quad \frac{d}{dx} \left( x^2 \right) + \frac{d}{dx} \left( y^2 \right) = \frac{d}{dx} \left( a^2 \right)\\\quad 2x + 2y \frac{dy}{dx} = 0\\\text{Solve for } \frac{dy}{dx}:\\\quad 2y \frac{dy}{dx} = -2x\\\quad \frac{dy}{dx} = \frac{-2x}{2y} = \frac{-x}{y}$$​​