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    If x : y = 3 : 5, then the value of (5x−3y)(10x+6y)\frac{(5x-3y)}{( 10x + 6y)}(10x+6y)(5x−3y)​​ is:
    Question

    If x : y = 3 : 5, then the value of (5x3y)(10x+6y)\frac{(5x-3y)}{( 10x + 6y)}​ is:

    A.

    1

    B.

    2

    C.

    0

    D.

    –1

    Correct option is C

    Given:
    ratio x : y = 3 : 5
    Solution:
    Let's assume x = 3k and y = 5k, where k is a constant.
    Now, substitute these values in the given expression:
     = (5x3y)(10x+6y)\frac{(5x - 3y)}{ (10x + 6y)}

    (5(3k)3(5k))(10(3k)+6(5k))\frac{(5(3k) - 3(5k))} { (10(3k) + 6(5k))}

    (15k15k)(30k+30k)\frac{(15k - 15k)} { (30k + 30k)}

    = 060k\frac{0} { 60k} ​= 0 ​​​​​

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