If we add 1 to the numerator and subtract 1 from the denominator of a given fraction, it becomes 1 . It becomes 2/3 if 1 is added to the denominator of the given fraction while the numerator is left unchanged. The fraction originally given is:

Correct option is B

Given:

​$$\frac{x}{y}$$​​

If 1 is added to the numerator and 1 is subtracted from the denominator, the fraction becomes 1

​$$\frac{x+1}{y-1} = 1$$​

If 1 is added to the denominator, the fraction becomes $$\frac{2}{3}$$​​

​$$\frac{x}{y+1} = \frac{2}{3}$$​

Solution:

3(y - 2) = 2y + 2

3y - 6 = 2y + 2

y - 6 = 2

y = 8

Now substitute y = 8 into

x = y - 2

x = 8 - 2 = 6