Correct option is C
Solution:Given:(l12w1)(l2−l3)+(l2w2)(l3−l1)+(l32w3)(l1−l2)=0Step 1:Observe the terms: (l12w1),(l2w2), and (l32w3). Each term shows a different dependence on length.Step 2:Statement 1: Weight of an empty ship varies as the square of the length, i.e., wempty∝l2.Statement 2: Weight of the ship’s cargo varies as the cube of the length, i.e., wcargo∝l3.Step 3:Thus, total weight of the ship is given by wtotal=wempty+wcargo.This means weight depends on both l2 and l3 terms.Step 4:Statement 3 says weight varies as sixth power of length.This is incorrect because sixth power would occur only if terms were multiplied, not added.Conclusion:Thus, Statement 1 and Statement 2 together are sufficient to satisfy the given relation.