If v = yzi + 3zxj + zk, then curl v is

Correct option is A

​$$\vec{u} = yz \, \hat{i} + 3zx \, \hat{j} + z \, \hat{k} \\[10pt]\text{Then } \nabla \times \vec{u} = \begin{vmatrix}\hat{i} & \hat{j} & \hat{k} \\\frac{\partial}{\partial x} & \frac{\partial}{\partial y} & \frac{\partial}{\partial z} \\yz & 3zx & z\end{vmatrix} \\[10pt]\nabla \times \vec{u} = \hat{i} \left( \frac{\partial (z)}{\partial y} - \frac{\partial (3zx)}{\partial z} \right) - \hat{j} \left( \frac{\partial (z)}{\partial x} - \frac{\partial (yz)}{\partial z} \right) + \hat{k} \left( \frac{\partial (3zx)}{\partial x} - \frac{\partial (yz)}{\partial y} \right) \\[10pt]\nabla \times \vec{u} = -3x \, \hat{i} + y \, \hat{j} + 2z \, \hat{k}$$​​