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If for any three non-null vectors ​​a⃗,b⃗,c⃗,(a⃗×b⃗)×c⃗=a⃗×(b⃗×c⃗)\vec{a}, \vec{b}, \vec{c}, \quad (\vec{a} \times \vec{b}) \times \vec{c} = \vec
Question

If for any three non-null vectors ​​a,b,c,(a×b)×c=a×(b×c)\vec{a}, \vec{b}, \vec{c}, \quad (\vec{a} \times \vec{b}) \times \vec{c} = \vec{a} \times (\vec{b} \times \vec{c}) then​

A.

vector a\vec{a} is perpendicular to b×c\vec{b}×\vec{c}​​

B.

a\vec{a} and b×c\vec{b}×\vec{c} are collinear​

C.

​vector b\vec{b} is perpendicular to a×c\vec{a}×\vec{c}​​

D.

b\vec{b} and a×c\vec{a}×\vec{c} are parallel.​

Correct option is D

Solution:(a×b)×c=a×(b×c)Use test vectors: a=i^,b=j^,c=k^a×b=k^,(a×b)×c=k^×k^=0b×c=i^,a×(b×c)=i^×i^=0Thus, b=j^,a×c=i^×k^=j^=>b and a×c are parallelCorrect answer: (D)\textbf{Solution:}\\ (\vec{a} \times \vec{b}) \times \vec{c} = \vec{a} \times (\vec{b} \times \vec{c}) \\[8pt]\text{Use test vectors: } \vec{a} = \hat{i}, \vec{b} = \hat{j}, \vec{c} = \hat{k} \\[4pt]\vec{a} \times \vec{b} = \hat{k}, \quad (\vec{a} \times \vec{b}) \times \vec{c} = \hat{k} \times \hat{k} = \vec{0} \\\vec{b} \times \vec{c} = \hat{i}, \quad \vec{a} \times (\vec{b} \times \vec{c}) = \hat{i} \times \hat{i} = \vec{0} \\[6pt]\text{Thus, } \vec{b} = \hat{j}, \quad \vec{a} \times \vec{c} = \hat{i} \times \hat{k} = -\hat{j} \\[4pt]\Rightarrow \vec{b} \text{ and } \vec{a} \times \vec{c} \text{ are parallel} \\[12pt]\boxed{\text{Correct answer: (D)}}​​

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