If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio 2:3, then the greater of the two angles is:

Correct option is C

Given : 

Two interior angles on the same side of a transversal intersecting two parallel lines ratio = 2 : 3 

Concept Used:

Two interior angle made by transversal line on parallel line are supplementary.
Solution : 

Let the two angles be 2x and 3x 

Then, 

2x + 3x = $$180^\circ$$​
5x =  $$180^\circ$$​
x =  $$36^\circ$$​
The angles are:
2x =  $$2\times36$$​ =  $$72^\circ$$​
3x =  $$3\times36$$​ =  $$108^\circ$$
Thus, the greater of the two angles is  $$108^\circ$$

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