If three numbers are in the ratio of 4 : 3 : 8 and the smallest of these numbers is 42, find the largest of these numbers.

Correct option is D

Given:

Ratio of three numbers = 4 : 3 : 8

Smallest number = 42

Solution:
Smallest ratio term = 3

x = $$\frac{42}{3} = 14$$​

Largest ratio term = 8

Largest number= 8 × 14 = 112