If the volume of cube is 29791 $$m^3$$​, then find the total surface area of cube in $$m^2.$$​​

Correct option is B

Given:
Volume of the cube =  $$29791 \, \text{m}^3 .$$​
Find the total surface area of the cube in $$\text{m}^2$$​​
Formula Used:
Volume of a cube:
​$$\text{Volume} = a^3$$​​
where  a  is the side length of the cube.
Total surface area of a cube:
​$$\text{Surface Area} = 6a^2$$​
Solution:
​$$a^3 = 29791$$​
​$$a = \sqrt[3]{29791}$$​​
​$$a = 31 \, \text{m}$$​
Now, calculate the total surface area using the formula:
​$$\text{Surface Area} = 6a^2$$​
​$$\text{Surface Area} = 6 \times (31)^2$$​
​$$\text{Surface Area} = 6 \times 961$$​
​$$\text{Surface Area} = 5766 \, \text{m}^2$$​
Thus, option (b) is right.