If the sum of five consecutive multiples of 2 is 660, then find the largest number.

If the sum of five consecutive multiples of 2 is 660.

Let the five consecutive multiples of 2 be:

2n, 2n + 2, 2n + 4, 2n + 6, 2n +8

The sum of these five numbers is given as 660:

2n +(2n+2) + (2n + 4) + (2n+6) +(2n + 8) = 660
2n + 2n + 2n + 2n + 2n + 2 + 4 + 6 + 8 = 660
10n + 20 = 660

10n = 660-20
10n = 640
n = 64

The largest number among the five multiples is:

2n + 8 

= 2(64) + 8

= 128+8

= 136

So, the largest number is 136.

Thus, the correct answer is (d).