Correct option is D
Given:
If the sum of five consecutive multiples of 2 is 660.
Solution:
Let the five consecutive multiples of 2 be:
2n, 2n + 2, 2n + 4, 2n + 6, 2n +8
The sum of these five numbers is given as 660:
2n +(2n+2) + (2n + 4) + (2n+6) +(2n + 8) = 660
2n + 2n + 2n + 2n + 2n + 2 + 4 + 6 + 8 = 660
10n + 20 = 660
2n + 2n + 2n + 2n + 2n + 2 + 4 + 6 + 8 = 660
10n + 20 = 660
10n = 660-20
10n = 640
n = 64
10n = 640
n = 64
The largest number among the five multiples is:
2n + 8
= 2(64) + 8
= 128+8
= 136
So, the largest number is 136.
Thus, the correct answer is (d).
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