If the side of a square is $$\frac{1}{10}$$​m, then how many such squares will get accommodated in a bigger square of side 4 m?

Correct option is D

Given:

The side of the smaller square is (1/10) m.

The side of the bigger square is 4m.

Formula Used:

Number of smaller squares accommodated = Area of the bigger square / Area of the smaller square.

Solution:

Area of the bigger square = $$4m \times 4m = 16m^2$$​​

Area of the smaller square = $$\left(\frac{1}{10}\right) m \times \left(\frac{1}{10}\right) m = \frac{1}{100}m^2$$​​

Number of smaller squares = $$\frac{16m^2}{\frac{1}{100}m^2} = 1600$$​​

Therefore, 1600 smaller squares can be accommodated in the bigger square.