If the ratio of the areas of two squares is 169 : 196, then the ratio of their perimeters is:

Correct option is A

Given:

Ratio of the areas of two squares = 169 : 196

Formula Used:

The area of a square is given by A = side²   

Perimeter of square = 4$$\times$$side​

Solution: ​

Ratios of Area's 

​$$\frac{{s}^2_1}{{s}^2_2}$$ = $$\frac{{169}}{{196}}$$ 

$$\frac{{s}_1}{{s}_2}$$ = $$\frac{\sqrt{169}}{\sqrt{196}}$$ 

​$$\frac{{s}_1}{{s}_2}$$ = $$\frac{13}{14}$$  

Now; we know

Ratio perimeter of square = $$\frac{4 \times s_1}{4 \times s_2} = \frac{s_1}{s_2}$$  

Thus, 

​The ratio of their perimeters is 13 : 14​