If the radius of a cylinder is doubled and the height is halved, then the volume change will be:

Correct option is C

Given:

Original radius = r

Original height = h

New radius = 2r

New height = $$\frac{h}{2}$$​​

Formula Used:

Volume of the cylinder = πr²h

Solution:

V original =$$\pi r^2 h$$​​

$$V_{\text{new}}$$​ = $$\pi (2r)^2 \times \frac{h}{2}$$​​

​$$= \pi \times 4r^2 \times \frac{h}{2}$$​​

​$$= 2 \pi r^2 h = 2V$$​​

Percentage increase = $$\frac{2V -V}{V} \times100 = 100\%$$​​