If the numerator of a fraction is increased by 30% and its denominator is decreased by 35%, the value of the fraction becomes$$\frac{3}{15}$$​. Find the original fraction.

Correct option is C

​Given:

Numerator increased by 30%.

Denominator decreased by 35%.

New fraction = $$\frac{3}{15} = \frac{1}{5}$$​

Solution:

Let the original fraction be $$\frac{x}{y}$$​ .

After changes:

​$$\frac{x + 0.3x}{y - 0.35y} = \frac{1}{5}$$​​

​$$\frac{1.3x}{0.65y} = \frac{1}{5}$$​​

$$5 \times 1.3x = 0.65y\\ \ \\ 6.5x = 0.65y \\ \ \\\implies y = 10x$$​​

Original fraction:

​$$\frac{x}{y} = \frac{x}{10x} = \frac{1}{10}$$​​