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    If the numerator of a fraction is decreased by 80% and the denominator of the fraction is decreased by 60%, then the resultant fraction is 56\frac{5}{
    Question

    If the numerator of a fraction is decreased by 80% and the denominator of the fraction is decreased by 60%, then the resultant fraction is 56\frac{5}{6}​. What is the original fraction?

    A.

    35\frac{3}{5}​​

    B.

    73\frac{7}{3}​​

    C.

    53\frac{5}{3}​​

    D.

    65\frac{6}{5}​​

    Correct option is C

    Given:
    Numerator is decreased by 80% → New numerator = 20% of original numerator = 15\frac{1}{5}​  of original
    Denominator is decreased by 60% → New denominator = 40% of original denominator =25 \frac{2}{5} of original
    Resultant fraction =56 \frac{5}{6} ​​
    Solution:
    Let the original fraction be xy \frac{x}{y} .​

    New numeratorNew denominator=15x25y=x2y\frac{\text{New numerator}}{\text{New denominator}} = \frac{\frac{1}{5}x}{\frac{2}{5}y} = \frac{x}{2y}​​
    x2y=56\frac{x}{2y} = \frac{5}{6}
    xy=56×2=106=53\frac{x}{y} = \frac{5}{6} \times 2 = \frac{10}{6} = \frac{5}{3}

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