Given:
The mean of a frequency distribution is 28, and the mode is 16.
Formula used:
Solution:
Median =
Median =
Median =
Median = 24
So, the median of the frequency distribution is 24.
Thus, the correct answer is (d).
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120 Mins English English100 Questions100 Marks120 Mins English English100 Questions100 Marks120 Mins EnglishIf x and y are upper limit of median class and lower limit of modal class, respectively in the following distribution, then what is the value of (2x + y)?
The following is the distribution of ages (in years) of children in a group:
What is the median age (in years) of children ?
The median of the observations 6, 48, 32, 3, 37 and 18 is:
In the following frequency distribution
| Height (in cm) | 140–145 | 145–150 | 150–155 | 155–160 | 160–165 | 165–170 |
| No. of students | 13 | 15 | 9 | 10 | 8 | 5 |
The sum of the upper limit of the modal class and the lower limit of the median class:
The median of a set of 9 distinct observations is 20.5. If each of the largest four observations of the set is increased by 2, then the median of the new set:
What is the median of the following data?
76, 35, 42, 49, 95, 21, 68, 41, 20, 27, 17
The mode and median of data are 36.3 and 62, respectively. What is the mean of the data?
(Use the empirical formula)
The mode and median of a dataset is 52.7 and 65, respectively. What is the mean of the dataset? (Use empirical formula, and round off your answer to one decimal place.)
Correct relation for the numbers 10, 7, 8, 5, 6, 8, 5, 8, 6 is:
The median of the observations 54, 65, 77, 34, 68, 66, 60, 70, 33, 71 and 15 is:
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Suggested Test Series
