If the mean of a frequency distribution is 28 and the mode is 16, then the median is:

Correct option is D

Given:
The mean of a frequency distribution is 28, and the mode is 16.

Formula used:

$$\text{Median} = \frac{\text{Mode} + 2 \times \text{Mean}}{3}$$​

​Solution:

​$$\text{Median} = \frac{\text{Mode} + 2 \times \text{Mean}}{3}$$

Median = $$\frac{16 + 2 \times 28}{3}$$​

Median = $$\frac{16 + 56}{3}$$​

Median = $$\frac{72}{3}$$​

Median = 24

So, the median of the frequency distribution is 24.

Thus, the correct answer is (d).