​If the height of a pole is $$6\sqrt{3}$$​ metre and the length of its shadow is 6 metre, then the angle of elevation of the sun is:

Correct option is A

Given:

Height of the pole = 636\sqrt{3}$$6\sqrt 3$$​ meters

Length of the shadow = $6$ meters

​Formula Used:

$$\tan(\theta) = \frac{\text{Height of the pole}}{\text{Length of the shadow}}$$

Solution:

Substitute the given values into the formula: 

​$$\tan(\theta) = \frac{6\sqrt{3}}{6} = \sqrt{3}$$ 

$$tan⁡(θ$$) = tan 60^​∘

θ = 60° 

Thus, option (A) satisfied

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