If the cost of a car and a bike are in the ratio of 3 : 2 and cost of the car is ₹15000 more than the bike, then find the cost (in ₹) of the bike.

Correct option is B

Given:

The cost of a car and a bike are in the ratio 3 : 2.

The car costs ₹15000 more than the bike.

Solution:

Let the cost of the car be 3x and the cost of the bike be 2x.

3x = 2x + 15000

3x - 2x = 15000

x = 15000

Cost of bike = 2 $$\times$$​ 15000 = 30000

Therefore, the cost of the bike is ₹30000.

Alternate Solution:

The difference of the ratio is 3-2 = 1.

This difference of 1 in the ratio represents ₹15000.

The bike has a ratio value of 2.

Therefore the bike cost is 2 $$\times$$ ₹15000 = ₹30000.​