If the circumference of the great circle of a hemisphere is 9 π cm, then find the total surface area of the hemisphere?

Correct option is B

Given:

Circumference of outer circle =$$9\pi cm$$​​

Formula Used:

Circumference of circle =$$2\pi r$$​​

Total surface area of hemisphere = $$3\pi r^2$$​​

Solution:

Circumference of circle = $$9 \pi cm$$​

​$$2 \pi r = 9 \pi$$​​

​$$r= \frac{9}{2}cm$$​​

Surface area of hemisphere =$$3\times\pi \times (r^2)$$​​

​$$= 3\times \pi \times (\frac{9}{2})^2$$​​

​$$= \frac{3 \times 81}{4} \pi cm^2$$​​

​$$= 60.75 \pi cm^2$$​​