The radius of a hemispherical bowl is 9 cm. The capacity of the bowls is:
(Use π = 22/7)

Correct option is D

Given:
Radius of the hemispherical bowl $$r = 9 \, \text{cm}$$​​
​$$\pi = \frac{22}{7}$$​

​Formula Used:

Volume of a hemisphere:

V = $$\frac{2}{3} \pi r^3$$​​

where r is the radius of the hemisphere.​​

Solution:

V = $$\frac{2}{3} \times \frac{22}{7} \times (9)^3$$​​

V = $$\frac{2}{3} \times \frac{22}{7} \times 729$$​

V =  $$\frac{2 \times 22 \times 729}{3 \times 7}$$​

V = $$\frac{32076}{21}$$​

V = $$1527.43 \, \text{cm}^3$$​​
The capacity of the hemispherical bowl is 1527.43 cm³
Thus, the correct option is (d)