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    If the breadth and height of a closed cuboid are, respectively, 25% and 50% of its length of 12 cm, then find the total surface area of this cuboid.
    Question

    If the breadth and height of a closed cuboid are, respectively, 25% and 50% of its length of 12 cm, then find the total surface area of this cuboid.

    A.

    126 cm2cm^2​​

    B.

    522 cm2cm^2​​

    C.

    63 cm2cm^2​​

    D.

    252 cm2cm^2​​

    Correct option is D

    Given:

    Length(ll ) = 12 cm 

    Breadth (b)(b) = 25% of length that is 3 cm

    Height (h)(h) = 50% of length that is 6 cm

    Formula used:

    Total Surface Area = 2(lb + bh + hl) 

    Solution: 

    Applying the formula: 

    Total Surface Area = 2(12×3 + 3×6 + 6×12)

    Total Surface Area = 2(36 + 18 + 72)

    Total Surface Area = 2×\times​(126)

    Total Surface Area = 252 cm2cm^2​​

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