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    If the annual rate of simple interest increases from 8% to 121212\frac{1}{2}1221​​%, a person's yearly income from interest increases by ₹369 then wha
    Question

    If the annual rate of simple interest increases from 8% to 121212\frac{1}{2}​%, a person's yearly income from interest increases by ₹369 then what is the principal amount of his investment?

    A.

    ₹8,100

    B.

    ₹8,500

    C.

    ₹8,150

    D.

    ₹8,200

    Correct option is D

    Given:

    Initial simple interest rate = 8% per annum

    New simple interest rate = 1212%12\frac{1}{2}\%​ per annum = 12.5% per annum

    Increase in yearly interest = ₹369

    Time = 1 year

    Concept Used:

    The simple interest formula:

    SI=P×R×T100\text{SI} = \frac{P \times R \times T}{100}

    Solution:

    P×12.5100P×8100=369\frac{P \times 12.5}{100} - \frac{P \times 8}{100} = 369​​

    P(12.58)100=369\frac{P (12.5 - 8)}{100} = 369​​

    P×4.5100=369\frac{P \times 4.5}{100} = 369​​

    P = 369×1004.5\frac{369 \times 100}{4.5}​​

    P =369004.5=8200 \frac{36900}{4.5} = 8200

    The principal amount is ₹8,200.

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