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If pq\frac{p}{q}qp​= 0.5, then  3p−q3p+q\frac{3p-q}{3p+q}3p+q3p−q​​ is:
Question

If pq\frac{p}{q}= 0.5, then  3pq3p+q\frac{3p-q}{3p+q}​ is:

A.

12\frac{1}{2}​​

B.

15\frac{1}{5}​​

C.

13\frac{1}{3}​​

D.

14\frac{1}{4}​​

Correct option is B

Given:

pq=0.5\frac{p}{q}=0.5​​

Solution:

3pq3p+q\frac{3p-q}{3p+q}​​

Taking q common from both numerator and denominator: 

q(3pq1)q(3pq+1)\frac{q(3\frac{p}{q}-1)}{q(3\frac{p}{q}+1)}​​

3pq13pq+1\frac{3\frac{p}{q}-1}{3\frac{p}{q}+1}​​

3(0.5)13(0.5)+1\frac{3(0.5)-1}{3(0.5)+1}​​

1.511.5+1\frac{1.5-1}{1.5+1}​​ = 0.52.5=15\frac{0.5}{2.5}= \frac{1}{5}

​​

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