If PQ and PR are the two tangents to a circle with center O, and ∠QOR=150°, then ∠QPR is equal to:

Correct option is B

Given:
∠QOR=150°
PQ and PR are the two tangents
Center of circle = O
Solution:
As per the question

Therefore, the radius drawn to these tangents will be perpendicular to the tangents. So, we have OQ⊥PQ and OR⊥RP. =>∠OQP=∠ORP=90∘ So, in quadrilateral PQOR, we have 

​$$\angle OQP + \angle QPR + \angle PRO + \angle ROQ = 360^\circ\\\Rightarrow 90^\circ + \angle QPR + 90^\circ + 150^\circ = 360^\circ\\\Rightarrow \angle QPR = 360^\circ - 330^\circ = 30^\circ\\$$​​