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If each side of a cube is decreased by 12%, then the percentage decrease in its surface area is:
Question

If each side of a cube is decreased by 12%, then the percentage decrease in its surface area is:

A.

25.66%

B.

28.23%

C.

22.56%

D.

26.54%

Correct option is C

Given: 

Each side of a cube is decreased by 12%

Formula Used:

Surface area of cube = 6a2

Solution:

Decrease in side = 12% = 12/100 = 3/25

Let Original side length = 25 unit

So, new side length = 25 - 3 = 22 

Original Surface area = 6×252=37506 × 25^2 = 3750​​

New Surface area = 6 × 22222^2​ = 2904

Decrease in surface area = 375029043750=8463750\frac{3750 - 2904}{3750} = \frac{846}{3750}​ × 100 = 22.56% 

Alternate Solution:

As we know surface are has two variable x and y 

here each side decreased by 12% 

means x = -12% and y = -12% 

Now, successive percentage;

= -12 -12 +(12)(12)100\frac{(-12)(-12)}{100} 

= -24 + 1.44 

= -22.56%(decrease)

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