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    If a loan grew 3 times in 6 years at Simple Interest, then how much time will it take to grow 8 times?
    Question

    If a loan grew 3 times in 6 years at Simple Interest, then how much time will it take to grow 8 times?

    A.

    15 years

    B.

    22 years

    C.

    20 years

    D.

    21 years

    Correct option is D

    Given:

    Let the principal (initial loan amount) be denoted as ( P ).
    If the loan grows 3 times in 6 years, the total amount after 6 years is ( 3P ), and the interest earned is ( 2P).

    Concept Used:
    The formula for Simple Interest (SI) is given by:
    SI=P×R×T100SI = \frac{P \times R \times T}{100}​​
    where (P) is the principal, (R) is the rate of interest per annum, and (T) is the time in years.
    From the information given, (2P) is the interest for 6 years. Using the Simple Interest formula:
    2P=P×R×61002P = \frac{P \times R \times 6}{100}​​
    R=2P×100P×6=2006=33.33%R = \frac{2P \times 100}{P \times 6} = \frac{200}{6} = 33.33\%​​
    Now, to grow the loan 8 times, the total amount will be ( 8P ), so the interest earned will be ( 7P ).
    We will use the same Simple Interest formula to find the time (T):
    7P=P×33.33×T1007P = \frac{P \times 33.33 \times T}{100}​​
    T=7P×100P×33.33=70033.3321 yearsT = \frac{7P \times 100}{P \times 33.33} = \frac{700}{33.33} \approx 21\text{ years}​​
    The loan will take approximately 21 years to grow 8 times.

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