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If a⊕b=a−b+1ab+(ab)a \oplus b = a-b + \frac{1}{\sqrt{ab}} + \sqrt{\left(\frac{a}{b}\right)}a⊕b=a−b+ab​1​+(ba​)​, then 0.9⊕0.1=?0.9\oplus 0.1 = ?0
Question

If ab=ab+1ab+(ab)a \oplus b = a-b + \frac{1}{\sqrt{ab}} + \sqrt{\left(\frac{a}{b}\right)}, then 0.90.1=?0.9\oplus 0.1 = ? ​

A.

30212\frac{30}{212}​​

B.

21430\frac{214}{30}​​

C.

21230\frac{212}{30}​​

D.

30214\frac{30}{214}​​

Correct option is B

Given:

ab=ab+1ab+(ab)a \oplus b = a-b + \frac{1}{\sqrt{ab}} + \sqrt{\left(\frac{a}{b}\right)}​​

Solution:

Here a = 0.9 and b = 0.1

0.90.1=0.90.1+1(0.9)(0.1)+(0.90.1)0.9 \oplus 0.1 = 0.9- 0.1 + \frac{1}{\sqrt{(0.9)(0.1)}} + \sqrt{\left(\frac{0.9}{0.1}\right)}​​

=0.8+1(0.09)+(91) = 0.8 + \frac{1}{\sqrt{(0.09)}} + \sqrt{\left(\frac{9}{1}\right)}​​

=0.8+10.3+3 = 0.8 + \frac{1}{0.3} + 3​​

=3.8+103= 3.8 + \frac{10}{3}​​

=3810+103= \frac{38}{10} + \frac{10}{3}​​

=114+10030=\frac{114+100}{30}​​

=21430=\frac{214}{30}​​

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