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If a : b = 5 : 3, then (a3−b3):(a3+b3)(a^3 - b^3) :(a^3+ b^3)(a3−b3):(a3+b3)​ = ?
Question

If a : b = 5 : 3, then (a3b3):(a3+b3)(a^3 - b^3) :(a^3+ b^3)​ = ?

A.

11:25

B.

49:16

C.

49:76

D.

25:76

Correct option is C

Given:

a:b =5:3

Formula Used:

Operation preference wiseSymbolBrackets[],,()Orders,of²(power),(root),ofDivision÷Multiplication×Addition+Subtraction\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}​​

Solution:

(a3b3)(a3+b3)\frac{(a^3 - b^3) }{(a^3+ b^3)}​​

=b3(a3b31)b3(a3b3+1)=\frac{b^3(\frac{a^3}{b^3} - 1) }{b^3(\frac{a^3}{b^3}+ 1)}​​

=(a3b31)(a3b3+1)=\frac{(\frac{a^3}{b^3} - 1) }{(\frac{a^3}{b^3}+ 1)}​​

=((53)31)((53)3+1)=\frac{((\frac{5}{3})^3 - 1) }{((\frac{5}{3})^3+ 1)}​​

=((12527)1)((12527)+1)=\frac{((\frac{125}{27}) - 1) }{((\frac{125}{27})+ 1)}​​

=(1252727)(125+2727)=\frac{(\frac{125-27}{27}) }{(\frac{125+27}{27})}​​

=(9827)(15227)=\frac{(\frac{98}{27}) }{(\frac{152}{27})}​​

=98152=\frac{98}{152}​​

=4976=49:76=\frac{49}{76} =49:76​​

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