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    If a:3=b:7=c:9a:3=b:7=c:9a:3=b:7=c:9​, then a+b+ca\frac{a+b+c}{a}aa+b+c​​ = ?
    Question

    If a:3=b:7=c:9a:3=b:7=c:9​, then a+b+ca\frac{a+b+c}{a}​ = ?

    A.

    319\frac{3}{19}​​

    B.

    19\frac{1}{9}​​

    C.

    193\frac{19}{3}​​

    D.

    13\frac{1}{3}​​

    Correct option is C

    Given:

    a : 3 = b : 7 = c : 9

    Solution:

    a3=b7=c9=k a=3k,b=7k,c=9k a+b+ca=3k+7k+9k3k=19k3k=193\frac{a}{3} = \frac{b}{7} = \frac{c}{9} = k \\ \ \\a = 3k,\quad b = 7k,\quad c = 9k \\ \ \\\frac{a + b + c}{a} = \frac{3k + 7k + 9k}{3k} = \frac{19k}{3k} = \frac{19}{3}

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