If 3x ∶ y ∶ 2z = 6 ∶ 5 ∶ 4 and 5x - 3y + 4z = 48, then find the value of 2z.

Correct option is A

Given:

3x ∶ y ∶ 2z = 6 ∶ 5 ∶ 4

Solution:

Let the ratio be 6k, 5k and 4k respectively

Then 3x = 6k ,x = 2k

y = 5k

2z = 4k , z = 2k

5x - 3y +4z =48

5(2k) - 3(5k) + 4 ( 2k) = 48

10k - 15k +8k = 48

3k = 48

k = 16 

then, 2z = $$4 \times 16 = \bf 64$$ ​