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    If 3(2/5) + 1(2/9) = 4(4/5) - a, find the value of 'a'.
    Question

    If 3(2/5) + 1(2/9) = 4(4/5) - a, find the value of 'a'.

    A.

    11/45

    B.

    16/9

    C.

    8/45

    D.

    6/25

    Correct option is C

    Given:

    3(25)+1(29)=4(45)a3\left( \frac{2}{5} \right) + 1\left( \frac{2}{9} \right) = 4\left( \frac{4}{5} \right) – a​​

    Solution:

    3(25)=175 1(29)=119 4(45)=245 175+119 175=15345,119=5545 15345+5545=20845 20845=245a 245=21645 20845=21645a a=2164520845=845 Therefore,thevalueofais845.3\left( \frac{2}{5} \right) = \frac{17}{5}\\\ \\1\left( \frac{2}{9} \right) = \frac{11}{9}\\\ \\4\left( \frac{4}{5} \right) = \frac{24}{5}\\\ \\\frac{17}{5} + \frac{11}{9}\\\ \\\frac{17}{5} = \frac{153}{45}, \quad \frac{11}{9} = \frac{55}{45}\\\ \\\frac{153}{45} + \frac{55}{45} = \frac{208}{45}\\\ \\\frac{208}{45} = \frac{24}{5} - a\\\ \\\frac{24}{5} = \frac{216}{45}\\\ \\\frac{208}{45} = \frac{216}{45} - a\\\ \\a = \frac{216}{45} - \frac{208}{45} = \frac{8}{45}\\\ \\Therefore, the value of a is \frac{8}{45}.​​

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