Correct option is CGiven:3(25)+1(29)=4(45)–a3\left( \frac{2}{5} \right) + 1\left( \frac{2}{9} \right) = 4\left( \frac{4}{5} \right) – a3(52)+1(92)=4(54)–aSolution:3(25)=175 1(29)=119 4(45)=245 175+119 175=15345,119=5545 15345+5545=20845 20845=245−a 245=21645 20845=21645−a a=21645−20845=845 Therefore,thevalueofais845.3\left( \frac{2}{5} \right) = \frac{17}{5}\\\ \\1\left( \frac{2}{9} \right) = \frac{11}{9}\\\ \\4\left( \frac{4}{5} \right) = \frac{24}{5}\\\ \\\frac{17}{5} + \frac{11}{9}\\\ \\\frac{17}{5} = \frac{153}{45}, \quad \frac{11}{9} = \frac{55}{45}\\\ \\\frac{153}{45} + \frac{55}{45} = \frac{208}{45}\\\ \\\frac{208}{45} = \frac{24}{5} - a\\\ \\\frac{24}{5} = \frac{216}{45}\\\ \\\frac{208}{45} = \frac{216}{45} - a\\\ \\a = \frac{216}{45} - \frac{208}{45} = \frac{8}{45}\\\ \\Therefore, the value of a is \frac{8}{45}.3(52)=517 1(92)=911 4(54)=524 517+911 517=45153,911=4555 45153+4555=45208 45208=524−a 524=45216 45208=45216−a a=45216−45208=458 Therefore,thevalueofais458.