If $$2^x = 4^{y+1}$$ and $$3^y = 3^{x-9}$$​, then the values of x and y, respectively, are:​

Correct option is A

Given:

​$$2^x = 4^{y+1}$$​ and$$3^y = 3^{x-9}$$​​,

Solution:

2^x=2^2(y+1)

Comparing power on both sides,

x = 2y+2

x - 2y = 2      ......(1) 

​$$3^y = 3^{x-9}$$​​

Comparing power on both sides,

y = x - 9

x - y = 9   ......... ( 2)

From equation 1 and 2, We have

x = 16, y = 7

Thus, option (A) is right.

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