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If (2x — 1) is a factor of 2x4—7x3+x+k=02x^4 — 7x^3+x + k=02x4—7x3+x+k=0​, then find the value of 'k’.
Question

If (2x — 1) is a factor of 2x47x3+x+k=02x^4 — 7x^3+x + k=0​, then find the value of 'k’.

A.

-5/12

B.

0

C.

1/4

D.

1

Correct option is C

Given:

(2x — 1) is a factor of 2x47x3+x+k=02x^4 — 7x^3+x + k=0​​

Solution:

2x-1=0

x=1/2

Put the value of x in equation to get the value of k

2x47x3+x+k=02x^4 — 7x^3+x + k=0 ​​

2(12)47(12)3+(12)+k=02(\frac{1}{2})^4 -7(\frac{1}{2})^3 +(\frac{1}{2}) +k=0​​

1878+48+k=0\frac{1}{8}-\frac{7}{8}+\frac{4}{8}+k=0​​

k =2/8

So, value of k =1/4.

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