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If 1.5x = 0.04y, then what will be the value of = (y−x)(y+x)\frac{(y-x)}{(y+x)}(y+x)(y−x)​ ?​
Question

If 1.5x = 0.04y, then what will be the value of = (yx)(y+x)\frac{(y-x)}{(y+x)} ?​

A.

73/77

B.

70/77

C.

77/73

D.

72/77

Correct option is A

Given:

1.5x = 0.04y

Solution:

1.5x = 0.04y

xy=0.041.5=4150=275\frac{x}{y} = \frac{0.04}{1.5} = \frac{4}{150} = \frac{2}{75}

Then the value of (yx)(y+x)\frac{(y-x)}{(y+x)}  = (752)(75+2)=7377\frac{(75-2)}{(75+2)} = \frac{73}{77}​​

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