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    How many water molecules are present in plaster of Paris?
    Question

    How many water molecules are present in plaster of Paris?

    A.

    Half molecules of water

    B.

    Zero molecules of water

    C.

    One molecule of water

    D.

    Three molecules of water

    Correct option is A

    The correct answer is: A) Half molecules of water
    Explanation:

    • Plaster of Paris (POP) is chemically Calcium Sulfate Hemihydrate (CaSO₄·½H₂O).
    • The formula indicates that for every molecule of CaSO₄, half a molecule of water is present.
    • POP is obtained by heating Gypsum (CaSO₄·2H₂O) at about 373K (100°C), which removes 1.5 water molecules, forming CaSO₄·½H₂O.
    Information Booster:
    • Formation Reaction:

    CaSO42H2OHeatCaSO4½H2O+1.5H2OCaSO₄·2H₂O \xrightarrow{Heat} CaSO₄·½H₂O + 1.5H₂O​​

    • Uses of POP:
    • Used in medical bandages (fractures).
    • Used for making statues, decorative items, and wall coatings.
    • Used in construction for quick-setting materials.
    • Rehydration of POP: POP reacts with water to form gypsum again.​

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