How many two-digit numbers are divisible by 5?

Correct option is C

Given:

Two-digit numbers range from 10 to 99.

Formula Used:

Number of multiples of 5 = $$\frac{\text{Last multiple} - \text{First multiple}}{5} + 1$$​​

Solution:

First two-digit multiple of 5 = 10

Last two-digit multiple of 5 = 95

Count = $$\frac{95 - 10}{5} + 1$$​​

​$$= \frac{85}{5} + 1$$​​

= 17 + 1 = 18