How many numbers between 1 and 100 are exactly divisible by 6 and 8 both?

Correct option is D

Given:

Range: 1 to 100

Find numbers divisible by both 6 and 8

Concept Used:
A number divisible by both 6 and 8 must be divisible by their LCM.

Solution:

LCM(6, 8) = $$2^3 \times 3$$​ = 24

​$$\left\lfloor \frac{100}{24} \right\rfloor$$​​

​$$\frac{100}{24} \approx 4.16$$​​

​Taking integer value of 4.16 = 4 ​

Thus, there are 4 numbers between 1 and 100 are divisible by both 6 and 8.