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    How many 4-digit numbers can be generated from the digits 1, 2, 3, 4, 5 and 6 such that 123 always appear as a string? No digit appears more than once
    Question

    How many 4-digit numbers can be generated from the digits 1, 2, 3, 4, 5 and 6 such that 123 always appear as a string? No digit appears more than once.

    A.

    8

    B.

    4

    C.

    6

    D.

    12

    Correct option is C

    Given:

    • Digits available: 1, 2, 3, 4, 5, 6
    • We need to form 4-digit numbers
    • The string 123 must appear together and in the same order
    • No digit repeats

    Concept Used:

    Treat "123" as a single block since it must appear together.
    Now, we are choosing 4-digit numbers, and one chunk is already "123" (3 digits together), so we only need to choose one more digit from the remaining digits.

    Solution:

    Step 1: Remaining digits after using 1, 2, 3 → {4, 5, 6}
    We need to pick 1 digit from these 3.

    So, number of ways to choose 1 more digit = 3

    Step 2: Total digits to arrange = 123 + 1 new digit = 4 digits

    We need to find how many ways to place "123" as a block along with the chosen digit.

    • For each such 4-digit number:
      • "123" can be placed in 2 ways:
        • At the start: "123X"
        • At the end: "X123"

    → So, for each selected extra digit, there are 2 positions

    Step 3: Final calculation:

    • Choose 1 digit from {4,5,6} = 3 ways
    • For each, 2 placements = 3 × 2 = 6 ways

    Correct Option: (C) 6

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