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How many 4-digit numbers can be generated from the digits 1, 2, 3, 4, 5 and 6 such that 123 always appear as a string? No digit appears more than once
Question

How many 4-digit numbers can be generated from the digits 1, 2, 3, 4, 5 and 6 such that 123 always appear as a string? No digit appears more than once.

A.

8

B.

4

C.

6

D.

12

Correct option is C

Given:

  • Digits available: 1, 2, 3, 4, 5, 6
  • We need to form 4-digit numbers
  • The string 123 must appear together and in the same order
  • No digit repeats

Concept Used:

Treat "123" as a single block since it must appear together.
Now, we are choosing 4-digit numbers, and one chunk is already "123" (3 digits together), so we only need to choose one more digit from the remaining digits.

Solution:

Step 1: Remaining digits after using 1, 2, 3 → {4, 5, 6}
We need to pick 1 digit from these 3.

So, number of ways to choose 1 more digit = 3

Step 2: Total digits to arrange = 123 + 1 new digit = 4 digits

We need to find how many ways to place "123" as a block along with the chosen digit.

  • For each such 4-digit number:
    • "123" can be placed in 2 ways:
      • At the start: "123X"
      • At the end: "X123"

→ So, for each selected extra digit, there are 2 positions

Step 3: Final calculation:

  • Choose 1 digit from {4,5,6} = 3 ways
  • For each, 2 placements = 3 × 2 = 6 ways

Correct Option: (C) 6

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