HCF of $$2^4 × 3^4 × 5^3 × 7^2$$​and $$2^2 × 3^6 × 5^5$$​is:

Correct option is D

Concept Used:

Hcf is the common term of multiple of numbers.

Solution:

Ist number =$$2^4 \times 3^4 \times 5^3 \times 7^2$$ 

Second number =$$2^2 \times 3^6 \times 5^5$$ 

HCF of these two terms = $$2^2 \times 3^4 \times 5^3$$ ​