For the following reaction, balance the chemical equation with state symbols.
​$$CO_2+H_2 O→C_6 H_12 O_6+6O_2+6H_2 O$$​​

Correct option is A

The correct answer is (A)

To balance the chemical equation with state symbols, let's carefully analyze the reaction. The equation represents the photosynthesis process in which carbon dioxide and water are converted into glucose, oxygen, and water.

Unbalanced Reaction:

$$\text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + \text{O}_2 + \text{H}_2\text{O}$$ 

Step 1: Balance Carbon (C):

On the left: 1 $$\, \text{C atom in CO}_2 \, \text{.} \\$$ 

On the right:  $$6 \, \text{C atoms in C}_6\text{H}_{12}\text{O}_6 \, \text{.} \\$$ 

Multiply $$CO_2$$ by 6. 

$$6\text{CO}_2 + \text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + \text{O}_2 + \text{H}_2\text{O}$$ 

Step 2: Balance Hydrogen (H):

On the left: Hydrogen is contributed by $$H_2O$$ Contribute Hydrogen:

On the right: 12 Hydrogen in $$\text{H atoms in C}_6\text{H}_{12}\text{O}_6 + 6 \, \text{H atoms in H}_2\text{O} \, \text{.} \\$$ 

Multiply $$H_2\text{O} \,$$​ on the left by  12: 

$$6\text{CO}_2 + 12\text{H}_2\text{O} \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 + \text{O}_2 + 6\text{H}_2\text{O}$$ 

Step 3: Balance Oxygen (O):

On the left: 12 from $$H_2O$$ and 12 from $$CO_2$$= 24 Oxygen atoms.

On the right: 6 in $$\text{O atoms in C}_6\text{H}_{12}\text{O}_6 + 6 \, \text{O atoms in O}_2 + 6 \, \text{O atoms in H}_2\text{O} = 24 \, \text{O atoms.} \\$$ 

The equation is now balanced. 

$$6\text{CO}_2 \,(\text{g}) + 12\text{H}_2\text{O} \,(\text{l}) \rightarrow \text{C}_6\text{H}_{12}\text{O}_6 \,(\text{aq}) + 6\text{O}_2 \,(\text{g}) + 6\text{H}_2\text{O} \,(\text{l})$$​​