Find the value of $$\frac{(19 × 9 +31 × 10 + 32 × 11)}{(233.25 × 2 - 50)}$$​​

Correct option is A

Given:

​$$\frac{(19 × 9 +31 × 10 + 32 × 11)}{(233.25 × 2 - 50)}$$​​

Formula Used:

​$$\begin {array}{|c|c|} \hline \textbf{Operation preference wise} & \textbf{Symbol} \\ \hline Brackets &[],{}, () \\ \hline Orders, of & ² (power), √ (root) , of \\ \hline Division & ÷ \\ \hline Multiplication & × \\ \hline Addition & + \\ \hline Subtraction & - \\ \hline \end{array}$$​

Solution:

= $$\frac{(19 × 9 +31 × 10 + 32 × 11)}{(233.25 × 2 - 50)}$$​​

= $$\frac{(171 +310 + 352)}{(466.50 - 50)}$$​​

= $$\frac{(833)}{(416.50)}$$​​

= 2