Find the smallest perfect square number which must be added to the number 12519 to get a perfect square number.

Correct option is D

Given:

We need to find the smallest perfect square number that must be added to 12519 so the result becomes a perfect square.

Solution:
Let the required perfect square be $$x^2$$​ such that:

​$$x^2 ≥ 12519$$​

Then:

Required number to add = $$x^2 - 12519$$​

​$$\sqrt{12519} \approx 111.88$$​​

Next integer = 112

​$$112^2 = 12544$$​​

Number to add = 12544 - 12519 = 25​

The smallest perfect square number to be added is 25.