Find the simple interest (in ₹) on ₹2000 at 6.25% per annum rate of interest for the period from 11 February 2023 to 25 April 2023.

Correct option is D

Given:

Principal P = ₹2000

Rate of interest R = 6.25% per annum

Time period = From 11 February 2023 to 25 April 2023

Formula Used:

Simple Interest$$= \frac{P \times R \times T}{100}$$​
where:

P = Principal amount

R = Rate of interest per annum

T= Time period in years

Solution:

The time period is from 11 February 2023 to 25 April 2023.

February has 28 days (2023 is not a leap year).

From 11 February to 28 February:

28 - 11  = 17 days

March has 31 days.

From 1 April to 25 April:

​$$17\,\text{days (February)} + 31\,\text{days (March)} + 25\,\text{days (April)} = 73\,\text{days}$$​

T =$$\frac{73}{365}\,\text{years}$$  

Now

​$$SI = \frac{P \times R \times T}{100}$$

​​$$SI = \frac{2000 \times 6.25 \times \frac{1}{5}}{100}$$

​​$$SI = \frac{2000 \times 6.25 \times 1}{500}$$​

​$$SI = \frac{12500}{500}$$

​SI $$= 25$$​
Option (D) is right.