Find the number of bricks, each measuring 24 cm $$\times$$ 12 cm $$\times$$ 8cm, required to construct a wall 24 m long, 8 m high and 60 cm thick if 10% of the wall is filled with mortar?​

Correct option is A

Given:
Measurement of bricks = 24 cm × 12 cm × 8 cm
Measurement of wall = 24m × 8m × 60cm
Formula Used:
Volume of cuboid = Length × Breadth × Height
Number of bricks = $$\frac{\text{Volume of wall}}{\text{Volume of each brick}}$$​​
Solution:
1 m = 100 cm
Volume of the wall in those bricks to be used = 2400 × 800 × 60 ×$$\frac {90}{100}$$​​
Volume of bricks = 24 × 12 × 8
Number of bricks =  $$\frac{\text{Volume of wall}}{\text{Volume of each brick}}$$​​
=> Number of bricks =  $$= \frac{2400 \times 800 \times 60 \times \frac{90}{100}}{24 \times 12 \times 8}$$​​
=> Number of bricks used= 45,000