Find the median of the below data.

2, 6, 5, 2,4, 9, 6, 2, 6, 4, 10, 12, 6, 3, 4, 9

Correct option is C

Given: 

2, 6, 5, 2,4, 9, 6, 2, 6, 4, 10, 12, 6, 3, 4, 9 

Formula Used:  

Median for the even number of terms;

= $$\frac{1}{2}\left[\left(\frac{{n}}2\right)^{\text{th }} \text{term} + \left(\frac{{n}}2+1\right)^{\text{th }} \text{term} \right]$$​  

Solution: 

​2, 6, 5, 2,4, 9, 6, 2, 6, 4, 10, 12, 6, 3, 4, 9  

arranging in  ascending order; 

2, 2, 2, 3, 4, 4, 4, 5, 6, 6, 6, 6, 9, 9, 10, 12

n = 16 (even)

Thus, 

Median ; 

​$$= \frac{1}{2} \left[\left(\frac{16}2\right)^{\text{th}} +\left(\frac{16}2+1\right)^{\text{th}}\right]$$ 

= $$\frac{1}{2}$$​ (8^th number +  9^thnumber)

=  ​$$\frac{5+6}2$$ = $$\frac{11}2$$ = 5.5 

Thus, the Option(c) 5.5 is correct. 

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